Sunday, February 28, 2021

The Chocolate Problem



For the solution, click "Read More" below.

Solution:


These are the numbers of chocolate bars that each party guest has at the time she sits down:

 

A=3, B=2, C=1 1/2, D=1, E=1, F=1, G= 3/4, H=2/3, I=3/5, J=1/2, K=1/2, L=1/2, . . . .

 

Notice that when D sits down, she can sit at any table and would get 1 chocolate bar.  So while different students may have different table arrangements in their solutions, these numbers should be the same for everyone.  

 

Can you find a pattern?  If you can, then you could start to explore larger numbers, such as where does the 100th person sit?


 

No comments:

Post a Comment

Note: Only a member of this blog may post a comment.

PLAYFUL MATH BLOG CARNIVAL #163

BLOG CARNIVAL #163....LET'S GO! Fun fact: The number 163 is prime, which we can prove simply by showing that it is not divisible by 2, 3...